2 Part Kinematic Equation Problem

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A car traveling at 75 ft/s passes a stationary police car, which then accelerates to catch up in 12 seconds. The displacement of the first car is calculated to be 900 feet. To catch up, the police car needs an acceleration of 12.50 ft/s². Using this acceleration, the final speed of the police car after 12 seconds is determined to be 150 ft/s. The discussion emphasizes the challenge of learning physics while confirming the calculations are correct.
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Homework Statement


A car driving at a constant speed of 75 ft/s passes a police car that is initially at rest. If the police car decides to give chase
A) What rate would the police have to accelerate to catch up with the other car in 12 seconds?
B) What is the police car's speed at the end of the 12 seconds?


Homework Equations


Use Kinematic Equations


The Attempt at a Solution


The first car's displacement would be 75 ft/s * 12 seconds = 900 feet? So if I use X = Vot + 1/2(at^2)that means that acceleration of the second car would have to be 12.50 ft/s Is this the correct? Or am I way off? So if the acceleration = 12.50 ft/s I use V = Vo + at and end up with Final V = 150 ft/s ? That just doesn't sound right to me, could you please try to explain what I'm doing wrong?
 
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Looks good to me. You're doing nothing wrong.
 
Well thank you :) I'm trying really hard to learn Physics. It's difficult for me to learn, but it's very interesting.
 
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