- #71
Killtech
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Thanks, that's easy enough. Okay, now I understand how to read a state like ##|n\rangle## in terms of measurement. What I still don't get though is how do you calculate conditional probabilities within this formalism? Or in other words how do you note any kind of entanglement between the sates? Well, in this case of a coherent beam everything is assumed to be independent so there is no entanglement anyway.vanhees71 said:It's sufficient to consider this for a single mode. [...]
But still still let's take it as a simple example anyway to proof the statement of @Cthugha that
So the simplest case would be to run the state ##|C_\alpha\rangle## through a beam splitter and calculate the conditional probabilities for measuring of beam given the results of measurement on the other. After the splitter can I write the state asCthugha said:All detection events are statistically completely independent foor coherent beams.
$$e^{-|\alpha_A^2|} \sum_{n=0}^{\infty} \frac {\alpha_A^n} {\sqrt{n!}} |A,n \rangle + e^{-|\alpha_B^2|} \sum_{n=0}^{\infty} \frac {\alpha_B^n} {\sqrt{n!}} |B,n \rangle$$
where ##A##,##B## are supposed to denote the two outgoing arms of the splitter? So again the Born rule would give me the probabilities and given that all vectors ##|A,n\rangle##, ##|B,n\rangle## are independent (i.e. orthogonal) the statement is perhaps trivial. Still how do I properly and formally calculate a conditional probability here? And how would I denote a state where the outgoing beams ##A##,##B## were statistically dependent, like for a most simple case of a single photon after passing the splitter?