2d Projectles Motion/Kinematics

[Jessicaelleig]

HI guys, I am having a lot of trouble with determining initial velocity, x and y components etc. Can someone please help me with this

Sara drives a rocket sled from rest 25 m up a 15 degree ramp at an acceleration of 8 m/s2. Whats the final velocity?

Thank you

 

[LowlyPion]

HI guys, I am having a lot of trouble with determining initial velocity, x and y components etc. Can someone please help me with this

Sara drives a rocket sled from rest 25 m up a 15 degree ramp at an acceleration of 8 m/s2. Whats the final velocity?

Thank you

The way the problem is worded means that the angle is of no concern because the m*g*Sin15 term is absorbed by the statement that it accelerates at 8m/s² up the ramp.

This suggests that you are only concerned with V² = 2*a*x

Of course the angle is of concern with regard to what happens after it leaves the ramp.

 

[baba89]

for reaching out for help with your project on projectile motion and kinematics. I understand that determining initial velocity, x and y components can be challenging, but I am here to assist you with understanding these concepts.

First, let's define some terms. Kinematics is the study of motion without considering the forces causing the motion, while projectile motion is the motion of an object through the air under the influence of gravity. In this case, Sara's rocket sled is experiencing projectile motion as it moves up the ramp.

To determine the final velocity of Sara's rocket sled, we can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.

Since Sara's rocket sled starts from rest (u = 0), we can simplify the equation to v^2 = 2as. We are given the acceleration (a = 8 m/s^2) and the displacement (s = 25 m), so we can plug these values into the equation and solve for v.

v^2 = 2(8 m/s^2)(25 m) = 400 m^2/s^2
v = √400 m^2/s^2 = 20 m/s

Therefore, the final velocity of Sara's rocket sled is 20 m/s.

To determine the x and y components of the initial velocity, we can use the equations ux = ucosθ and uy = usinθ, where ux is the x component of the initial velocity, uy is the y component of the initial velocity, u is the initial velocity, and θ is the angle of the ramp (15 degrees in this case).

Plugging in the values, we get:
ux = ucos15 = u(0.96) = 0.96u
uy = usin15 = u(0.26) = 0.26u

Therefore, the x and y components of the initial velocity are 0.96u and 0.26u, respectively.

I hope this explanation helps you understand the concepts of initial velocity and components in projectile motion. If you have any further questions, please do not hesitate to ask. Best of luck with your project!