Am I crazy, or does 11pi/4 lie in quadrant 3?

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11pi/4 is indeed in quadrant 2, as it can be expressed as 2pi + 3pi/4, which aligns with the position of 3pi/4. The confusion arose from misreading the original question, which actually referred to t = -11pi/4. This negative angle would place it in quadrant 3. The discussion highlights the importance of accurately interpreting mathematical problems. Understanding the unit circle is crucial for determining the correct quadrant for given angles.
LordofDirT
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Am I crazy, or does 11pi/4 lie in quadrant 3? That's what the back of my book says. But when I count it out on the unit circle it lands in quadrant 2 where 3pi/4 is located.
 
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11pi/4=2pi+3pi/4. So it lies in the same quadrant as 3pi/4. You aren't crazy.
 
Actually, I think I really am. The original question was asking for t = -11pi/4, which would put me at quadrant 3.

Thanks
 
Well, at least you know how to do the problem. Now you just have to learn to read it correctly.
 

Thread 'Find the polar form of a complex number'

The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.
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