Analyzing an Electron's Velocity Vector Problem

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The discussion focuses on solving a problem related to an electron's velocity vector, with specific emphasis on parts (c) and (d) that involve calculating the magnitude and angle of the velocity at t=6.00 seconds. The user successfully derived the electron's velocity in unit-vector notation for parts (a) and (b). For part (c), the magnitude of the velocity vector can be found by squaring each component, summing them, and taking the square root. To determine the angle with the positive x-axis in part (d), the dot product formula is applicable. The user ultimately resolved their confusion and thanked the community for assistance.
0aNoMaLi7
One part of this problem has me confused...id appreciate any guidance. I have part (a) and (b) but (c) and (d) are TOTALLY losing me. i don't even know where to begin. THANKS :smile:

"An electron's position is given by r=3.00t i - 5.00t^2 j + 3.00 k, with t in seconds and r in meters"

(a) In unit-vector notation, what is the electron's velocity v(t)?
My answer: 3.00 i - 10.0t j+ 0.00 k

(b) What is v in unit-vector notation at t=6.00s?
My answer: 3.00 i - 60.0 j+ 0.00 k

(c) What is the magnitude of v at t = 6.00 s? :eek:

(d) What angle does v make with the positive direction of the x-axis at t = 6.00 s? :eek:

Thank you.
 
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To find the magnitude of a vector just square each component, add them up and find the square root.

You can find the angle between two vectors using the "dot product:"

\vec A \cdot \vec B = A B \cos \phi

where A and B are the magnitudes of the vectors and \phi is the angle between them.
 
thanks... solved it :-)
 
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