Angular acceleration of tires on a car

AI Thread Summary
The discussion focuses on calculating the angular acceleration of car tires given specific parameters, including a final velocity of 22.0 m/s reached in 111 seconds and a tire radius of 0.320 m. The initial approach involved finding linear displacement, rotations, and angular displacement, but the calculated angular acceleration was initially incorrect at 0.0141 rad/s². Clarifications were made regarding the relationship between linear and angular quantities, leading to the realization that the correct angular acceleration should be 0.619 rad/s². The conversation highlights the importance of understanding the formulas connecting linear and angular motion in solving such physics problems.
Spartan301
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Homework Statement


You accelerate your car from rest at a constant rate down a straight road and reach 22.0 m/s in 111s. The tires on your car have radius 0.320 m. Assuming the tires rotate in a counterclockwise direction, what is the angular acceleration of the tires?

Homework Equations


Givens:
Initial velocity: 0
Final velocity: 22.0 m/s
Elapsed time: 111s
Tire radius: 0.320 m

Objective: Find the angular acceleration of the tires.

Battle Plan:
Find the linear displacement from the average acceleration and the elapsed time.
(vf² = vi² + 2aΔx)
Find the circumference of the tires from the radius, and divide the linear displacement by the circumference to find the number of rotations in that length.
Use ΔΘ = Θf-Θi, having multiplied the number of full rotations by 2π.
Divide the angular displacement by the elapsed time to find angular velocity.
Divide the change in angular velocity by the elapsed time to find angular acceleration

The Attempt at a Solution


Outcome:
a = 0.198198198
vf² = vi² + 2aΔx
vf² - vi² = 2aΔx
(vf² - vi²)/2a = Δx
22 m²/s² / 2(0.198198198 m/s^2) = Δx
22 m²/s² / 0.396396396 m/s^2
Linear displacement: 55.5 m

Radius: 0.320 m
Circumference = 2π(0.320m) = 2.010619298 m

55.5 m/ 2.010619298 m = 27.60343544 rotations.

27.60343544 rotations x 2π = 173.4375 radians

173.4375 radians/ 111s = 1.5625 rad/s

1.5625 rad/s / 111s = 0.014076577 rad/s²

They say the answer is supposed to be 0.619 rad/s²

Thank you for your help. Let me know if I can return the favor.

-Tom
 
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Hi Tom! :smile:

linear displacement = r x angular displacement: s = rθ

linear speed = r x angular speed: v = rω

linear acceleration = r x angular acceleration: a = rα :wink:
 
Thanks for replying Tim.

tiny-tim said:
Hi Tom! :smile:

linear displacement = r x angular displacement: s = rθ

linear speed = r x angular speed: v = rω

linear acceleration = r x angular acceleration: a = rα :wink:

I do not understand.
 
Spartan301 said:
The tires on your car have radius 0.320 m … what is the angular acceleration of the tires?

a = 0.198198198

They say the answer is supposed to be 0.619 rad/s²

a = rα :wink:
 
Ooooh! Now I understand! Good job! Thank you!
 
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