- #1
hidemi
- 208
- 36
- Homework Statement
- A 2.00 m-long 6.00 kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0 kg trapeze artist climbs to a point where her center of mass is at the center of the ladder and swings at the system's natural frequency. The angular frequency (in s −1) of the system of ladder and woman is
A) 1.01
B) 3.07
C) 4.03
D) 8.05
E) 16.2
The answer is B.
- Relevant Equations
- w= √(mgd/I)
I calculate as follow and get a correct answer, but I wonder why the weight of the ladder 6 kg is not included in the mass (m) in the numerator.
w= √(mgd/I)
= √ { (42*10*1)/ [(1/12)(6)(2^2)+42*1] }
w= √(mgd/I)
= √ { (42*10*1)/ [(1/12)(6)(2^2)+42*1] }