Angular Momentum of a Moving Particle

In summary, the conversation discusses a point particle traveling in a straight line at constant speed and the closest distance it comes to the origin of coordinates. The question is whether the particle has nonzero angular momentum with respect to the origin and whether its angular momentum changes as it moves along its path. The equations L = r x p and the assumption that there are no external torques applied are used to determine that the angular momentum does not change, but the angular momentum vector may change due to the changing position vector of the particle.
  • #1
Mark Zhu
32
3

Homework Statement


A point particle travels in a straight line at constant
speed, and the closest distance it comes to the origin of coordinates
is a distance l. With respect to this origin, does the particle
have nonzero angular momentum? As the particle moves along its
straight-line path, does its angular momentum with respect to the
origin change?

Homework Equations


L = r x p

The Attempt at a Solution


Since there are no external torques applied to this particle system, I assume the angular momentum doesn't change. However, since the position vector of the particle changes over time and the linear momentum vector remains constant, wouldn't the angular momentum vector also change looking at the L = r x p
equation?
 
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  • #2
Mark Zhu said:

Homework Statement


A point particle travels in a straight line at constant
speed, and the closest distance it comes to the origin of coordinates
is a distance l. With respect to this origin, does the particle
have nonzero angular momentum? As the particle moves along its
straight-line path, does its angular momentum with respect to the
origin change?

Homework Equations


L = r x p

The Attempt at a Solution


Since there are no external torques applied to this particle system, I assume the angular momentum doesn't change. However, since the position vector of the particle changes over time and the linear momentum vector remains constant, wouldn't the angular momentum vector also change looking at the L = r x p
equation?
I see this is marked solved. Please confirm with a post to the thread.
 
  • #3
Yes, it is solved. Thanks.
 

FAQ: Angular Momentum of a Moving Particle

What is angular momentum?

Angular momentum is a physical quantity that measures the amount of rotation an object possesses. It is defined as the product of an object's moment of inertia and its angular velocity.

How is angular momentum different from linear momentum?

Linear momentum is a measure of an object's motion in a straight line, while angular momentum is a measure of an object's rotational motion. Linear momentum is a vector quantity, while angular momentum is a vector quantity that also has direction and magnitude.

What is the formula for angular momentum of a moving particle?

The formula for angular momentum of a moving particle is L = Iω, where L is angular momentum, I is moment of inertia, and ω is angular velocity.

What is the conservation of angular momentum?

The conservation of angular momentum is a fundamental law of physics that states that the total angular momentum of a closed system remains constant, unless an external torque acts on the system. This means that the total angular momentum before an event is equal to the total angular momentum after the event.

How is angular momentum used in science and engineering?

Angular momentum is used in various fields of science and engineering, including astronomy, mechanics, and fluid dynamics. It is used to describe the rotation of planets, satellites, and other celestial bodies, as well as the motion of objects in fluids. It is also used in the design and analysis of machines and structures that involve rotation, such as turbines and gyroscopes.

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