- #1
Satvik Pandey
- 591
- 12
Homework Statement
Find out the angular momentum of particle as it reaches the highest point about the origin in projectile?
m=1 kg angle(i)=60 degree(with horizontal) u=10 m/s g=10
Homework Equations
The Attempt at a Solution
As angular momentum=##mrvsinB ##
Here velocity at top=##ucos\theta ##
As sinB=h/r
h=rsinB
Now h=##\frac { { u }^{ 2 }{ sin }^{ 2 }\theta }{ 2g } ##
So angular momentum=##\frac { { u }^{ 2 }{ sin }^{ 2 }\theta }{ 2g } ## ##mucos\theta ##
On putting values I got
##\frac { 100{ sin }^{ 2 }(60) }{ 2\times 10 } 10cos(60)##
##5{ sin }^{ 2 }(60)10cos(60)##
##\frac { 15 }{ 4 } \times \frac { 10 }{ 2 } =18.75##
But the answer is 187.5[/B]