Angular momentum quantum mechanics

AI Thread Summary
The discussion focuses on a spin-less particle confined to a sphere, with the Hamiltonian expressed as H=L_op^2/(2M) in spherical coordinates. The energy eigenvalues are confirmed to be l(l+1)ħ², with the degeneracy determined by the number of possible m values for a given l, which is 2l+1. Participants clarify that l can take integer values starting from 0, and the need for another commuting operator to fully specify the system is emphasized. The concept of degeneracy is linked to the dimensions of SU(2) and the representation of particles in quantum mechanics. Understanding these relationships is crucial for a complete analysis of the system.
thenewbosco
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Consider a spin-less particle, mass M, confined on a sphere radius 1. It can move freely on the surface but is always at radius 1.
1. Write the Hamiltonian H=\frac{L_{op}^2}{2M} in spherical polar coords.
2. Write the energy eigenvalues, specify degeneracy of each state. (not you can omit r part of wavefunction, concentrate on \theta and \phi dependence)

I have done part one. but i am not sure how to go about part two. I am thinking that it will be just the operator L^2 acting on a ket like |l m> ? then the eigenvals are l(l+1)hbar^2? i don't see where the degeneracy will come in...any help?
 
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You have the right idea for the eigenvalues. For the degeneracies, think of how many states have the eigenvalue l(l+1)hbar^2. More directly, how many m's are possible for a given l?
 
since m=-l...+l we have 2l+1, m values. how do i know which integers i will have for l in this case, would it be just 0 and 1? Since the hamiltonian has degeneracy, how can i find what else i need to specify a complete set of commuting observables?
 
thenewbosco said:
since m=-l...+l we have 2l+1, m values. how do i know which integers i will have for l in this case, would it be just 0 and 1? Since the hamiltonian has degeneracy, how can i find what else i need to specify a complete set of commuting observables?

think what mean 2l+1: It is the dimension of SU(2) in function of the spin (weight) of the particle. In Our formal theories particles are just representations of groups, or maybe some tracks in experiments... well in any way you have a spinless particle...

bye
marco
 
You just need another operator that has eigenvalues that are functions of m that also commutes with the Hamiltonian.
 
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