Answer: Volume of 4π/3 x 6495kg/m³ x 0.026m³ in kg

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The calculation involves finding the volume using the formula 4π/3 x 6495 kg/m³ x (0.026 m)³, which results in units of kilograms since the cubic meters cancel out. The primary concern is ensuring the answer is expressed with the correct number of significant figures. The integers 4 and 3 have unlimited significant figures, while the value 0.026 has two significant figures, which dictates the final answer's precision. Therefore, after performing the computation, the result should be rounded to two significant figures. The final answer will be expressed in kilograms.
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Express the answer with the correct units and to the correct number of significant digits:

4pi/3(6495 kg/m^3)(0.026m)^3

-I know that the units in the answer would be kg because the m^3's will cancel.
-It is the sig figs that are giving me trouble. (perhaps the "pi" is screwing me up)

Thanks
 
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The "4" and the "3" seem to be integers and have unlimited significant figures, thereby not limiting the figures in the result. The 0.026 seems to have the fewest, therefore, TWO significant figures. Adjust your answer to two significant figures (AFTER performing your computation, not before).
 
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