Are Irreducible Polynomials of Degree 4 Always Reducible?

  • Thread starter Thread starter letmeknow
  • Start date Start date
  • Tags Tags
    Degree
letmeknow
Messages
26
Reaction score
0
Proposition. A polynomial of degree 2 or 3 over a field F is reducible iff it has a root in F.

Tell me if I'm on the right track... I see that x^4 + 3x^2 + 2 is reducible (x^2+1)(x^2+2) but has no roots in Q.

This serves as a counterexample to the proposition if states for polynomial up to degree 4?
 
Physics news on Phys.org
Yes, that serves as a counter example for polynomials of degree 4. And that's why your proposition only says "degree 2 or 3".

If a polynomial of degree three is "reducible", then it must be "reduced" to two linear factors. And those two linear factors will give roots. If a polynomial of degree three is "reducible" then it is "reduced" to either a product of three linear factors or a product of a linear factor and an irreducible quadratic. In either case, you have at least one linear factor that gives a root.
 
Last edited by a moderator:
The world of 2\times 2 complex matrices is very colorful. They form a Banach-algebra, they act on spinors, they contain the quaternions, SU(2), su(2), SL(2,\mathbb C), sl(2,\mathbb C). Furthermore, with the determinant as Euclidean or pseudo-Euclidean norm, isu(2) is a 3-dimensional Euclidean space, \mathbb RI\oplus isu(2) is a Minkowski space with signature (1,3), i\mathbb RI\oplus su(2) is a Minkowski space with signature (3,1), SU(2) is the double cover of SO(3), sl(2,\mathbb C) is the...
Back
Top