- #141
- 8,943
- 2,949
DarMM said:The wavefunctions in QFT are of the form (in the Heisenberg picture):
$$\Psi(\phi), \quad \phi \in \mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right), \quad \Psi \in \mathcal{H} = \mathcal{L}^{2}\left(\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right),d\nu\right)$$
with ##\mathcal{S}^{'}\left(\mathbb{R}^{d-1}\right)## the space of tempered Schwarz distributions on a spacelike slice. Depending on the measure ##d\nu## the Hilbert space has a Fock decomposition.
Yes. In going from non-relativistic quantum mechanics to quantum field theory, I originally found it confusing because I thought of ##\phi## as the analogy for the nonrelativistic wave function, when it's actually ##\Psi##. The confusion is made worse by the fact that the Heisenberg equations for ##\phi## look (at least for free fields) like the Schrodinger equation for the single-particle wave function.