What is the formula for finding the area of a non-symmetric oval shape?

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The area of an ellipse is calculated using the formula A = πab, where a is the length of the minor axis and b is the length of the major axis. For non-symmetric oval shapes, a specific formula is not universally defined; instead, integration of the bounding curves is required to determine the area. The discussion highlights that while the ellipse is a well-known shape, other oval forms may require unique mathematical approaches based on their specific characteristics. Additionally, the conversation touches on the generalization of ovals through equations that can create various shapes depending on the exponent used. Understanding these concepts is essential for accurately calculating areas of different oval shapes.
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i want to know if there is a formula for the area of an oval shape because i have been working on it and want to know if it has been discovered
 
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What's the mathematically correct term for "oval"...?

Daniel.
 
abia ubong said:
i want to know if there is a formula for the area of an oval shape because i have been working on it and want to know if it has been discovered
hint: integrate the formula for an ellipse, using the boundaries carefully, and making sure that you sum any "negative" portions of the graph seperately.

or you could just look it up in a book, i suppose...but that would be no fun.
 
abia ubong said:
i want to know if there is a formula for the area of an oval shape because i have been working on it and want to know if it has been discovered

If you mean an ellipse, then, yes, I would think the formula has been known for centuries. It's actually trivial to derive it yourself.

The ellipse is basically a stretched version of the circle. It's said to have a shorter minor axis, a and a longer major axis, b. These axes are the analogues of the (uniform) radius of a circle. Observe that if you took a circle of radius a and stretched it by a factor of \frac{b}{a} in one direction, you'd have the exact shape of the ellipse.

So we'll use that fact. Since the ellipse is stretched in only one dimension with respect to the circle, the ratio of the areas of the ellipse to the circle is going to be simply \frac{b}{a}. We know that area of the circle is \pi a^2. (I'm not going to derive this here, I'm assuming you've seen proofs of that before).

So,

A_{ellipse} = A_{circle}(\frac{b}{a}) = \pi a^2 (\frac{b}{a}) = \pi ab

So the area of the ellipse is simply \pi ab, Pi times the minor axis times the major axis.
 
But, if by oval, you mean the classical "egg" shape, the cross section of which has only one axis of symmetry, then you need to have a well defined formula (Cartesian or polar) for the bounding curves, then use integration to find the area bounded by the curves.
 
Curious3141 said:
But, if by oval, you mean the classical "egg" shape, the cross section of which has only one axis of symmetry, then you need to have a well defined formula (Cartesian or polar) for the bounding curves, then use integration to find the area bounded by the curves.

Many years ago my sister gave me a Christmas present that was a lump of brass in the shape of a solid of revolution with a central cross section given by the equation

\left[\frac{|x|}{a}\right]^n + \left[\frac{|y|}{b}\right]^n = 1

I don't recall the value for n that was used, but it was chosen to make the thing have stable equilibrium while standing on end, but just barely. On a flat surface it would roll nicely end to end, bobbing up and down, and had some nice characteristics for spinning more or less about the long axis. I seem to recall the shape had been used by some architects to design a sports arena.

It is an interesting generalization of a symmetric oval, of which the ellipse is a special case. In general, n need not be an integer (I think it was not for my little novelty; it was probably about 2.5). With n = 1, it is a diamond. With n < 1 it has a concave cross section. With n > 1 you can generate oblong shapes comparable to oblong balls like those used in football and rugby. In fact, you can have different exponents on the two terms. With different exponents you can fine tune the "pointiness" of the ends
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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