[ASK] Exponents and Roots Simplification problem

[Monoxdifly]

The result of \(\displaystyle \frac{7x-\frac92\sqrt[6]{y^5}}{\left(x^{\frac56}-6y^{-\frac13}\right)x^{-2}}\) for x = 4 and y = 27 is ...
a. \(\displaystyle \left(1+2\sqrt2\right)9\sqrt2\)
b. \(\displaystyle \left(1+2\sqrt2\right)9\sqrt3\)
c. \(\displaystyle \left(1+2\sqrt2\right)18\sqrt3\)
d. \(\displaystyle \left(1+2\sqrt2\right)27\sqrt2\)
e. \(\displaystyle \left(1+2\sqrt2\right)27\sqrt3\)

I got stuck at \(\displaystyle \frac{56-3^2\left(3^{\frac52}\right)}{2^-{\frac43}-2^{-2}}\) and don't know how to continue to reach one of the options. By the way, don't you think that 7 is suspicious?

 

[skeeter]

I simplified the original expression to $\dfrac{4(56-81\sqrt{3})}{\sqrt[3]{4}-1}$

Note evaluation of the original numerator ...

$28 - \frac{9}{2} \cdot 27^{5/6} \approx -42.1481$

evaluation of the denominator ...

$(4^{5/6} - 6\cdot 27^{-1/3}) \cdot \frac{1}{16} \approx 0.0734$

Division would yield a negative value. Clearly, all choices are positive. Maybe a typo or other error with the original expression?

 

[Monoxdifly]

Division would yield a negative value. Clearly, all choices are positive. Maybe a typo or other error with the original expression?

According to you, what part of the question should be gotten rid of to reach one of the options?

 

[skeeter]

According to you, what part of the question should be gotten rid of to reach one of the options?

Something is in error with the original expression. Could be an omission, a sign error, a coefficient error, an error in one or more exponents, or a combination of the aforementioned.

You can make an attempt to reverse engineer the original expression to fit one of the choices if you have the time and the inclination.

 

[Monoxdifly]

You can make an attempt to reverse engineer the original expression to fit one of the choices if you have the time and the inclination.

I don't. Especially when I don't even know what's the supposed right answer. Not going to waste my time reverse-engineering up to five options. Gonna raise my white flag.

 

[DavidCampen]

I simplified the original expression to $\dfrac{4(56-81\sqrt{3})}{\sqrt[3]{4}-1}$

I can duplicate Skeeters answer. I wouldn't have had the patience to try simplifying the original expression if Skeeter hadn't already given the answer. It was very tedious and I had to go over it several times to correct mistakes. They must make software to do this.

 

[Wilmer]

Mr.Fly, you posted a "bad" expression, obviously.

Go stand in the corner for y minutes...

 

[Wilmer]

By the way, don't you think that 7 is suspicious?

Well, if that 7 was 20, then you'd be "in the range", with result = ~134.17,
between 3rd choice of ~119.36 and 4th choice of ~146.18.

 

[Monoxdifly]

Well, someone at MIF already did modify the question to match one of the options:
[ASK] Exponents and Roots (Page 1) / Help Me ! / Math Is Fun Forum

 

[Wilmer]

Holy crappy!

So numerator: 7 * x * 9^(1/2) * y^(5/6)
denominator : [x^(5/4) - 6 * y^(-1/3)] * x^(1/2)

which matches the 5th choice...

Remind me not to look at any of your future equations :)

 

[DavidCampen]

Well, someone at MIF already did modify the question to match one of the options:
[ASK] Exponents and Roots (Page 1) / Help Me ! / Math Is Fun Forum

Or someone could modify one of the answers to match the question. How do you decide which is correct?

 

[Monoxdifly]

Remind me not to look at any of your future equations :)

Dude, that's harsh!

 

[Wilmer]

Dude, that's harsh!

No...no...I said that with my heart :)