MHB ASVAB Find Angle CAD: Using Alternate Interior Angles

Thread starter karush
Start date May 12, 2021
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Angle Cad

May 12, 2021

karush

Gold Member

MHB

OK wanted to see how a transparent image would look like here:unsure:

well first $\angle{BAC}=57^o$ by alternate interior angle are equal

and then...

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May 13, 2021

skeeter

$m \angle CBA + m \angle BAC + m \angle CAD = 180^\circ$

May 13, 2021

karush

Gold Member

MHB

well that would shorten the rabbit chase on this one

Thread 'Trigonometry problem of interest'

Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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Thread 'Midpoint(s) of the unbounded number line'

Just chatting with my son about Maths and he casually mentioned that 0 would be the midpoint of the number line from -inf to +inf. I wondered whether it wouldn’t be more accurate to say there is no single midpoint. Couldn’t you make an argument that any real number is exactly halfway between -inf and +inf?

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Thread 'Arithmetic and our place value system'

A power has two parts. Base and Exponent. A number 423 in base 10 can be written in other bases as well: 1. 4* 10^2 + 2*10^1 + 3*10^0 = 423 2. 1*7^3 + 1*7^2 + 4*7^1 + 3*7^0 = 1143 3. 7*60^1 + 3*60^0 = 73 All three expressions are equal in quantity. But I have written the multiplier of powers to form numbers in different bases. Is this what place value system is in essence ?

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MHB ASVAB Find Angle CAD: Using Alternate Interior Angles

Thread 'Trigonometry problem of interest'

Thread 'Midpoint(s) of the unbounded number line'

Thread 'Arithmetic and our place value system'

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