Atwood Machine: Energy & Work Homework Soln

AI Thread Summary
The discussion revolves around solving an Atwood machine problem involving a 4.92-kg block on a ledge and a 2.46-kg hanging block, with a pulley that has mass and radius. The user initially struggled with the work done by forces and considered the tension in the string. They sought a simpler method to calculate the speed of the falling block after it descends 2.67 m. A suggestion was made to use energy conservation principles, which would simplify the calculations without needing to analyze acceleration details. The importance of accounting for the pulley’s mass in the energy conservation approach was also highlighted.
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Homework Statement



An atwood machince has a m1 = 4.92-kg block resting on a frictionless horizontal ledge. This block is attached to a string that passes over a pulley, and the other end of the string is attached to a hanging m2 = 2.46-kg block.


The pulley is a uniform disk of radius 8.06 cm and mass 0.615 kg. Calculate the speed of the m2 = 2.46-kg block after it is released from rest and falls a distance of 2.67 m.

Homework Equations



Work = ∫F dot ds

ΔE = ΔKE(translation) = 1/2*m2*vf^2 - 1/2*m2*vi^2


The Attempt at a Solution


At first I assumed only the weight force was doing work on mass 2 but I got the wrong answer. Then I thought perhaps tension was also doing work on mass 2. In order to find the tension force, I need to find the torques acting on the pulley and the sum of the forces acting on mass 1. I can do all of this, however, I would like to know if there is an easier, less complex way to do this problem.
Thanks!
 
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You can use energy conservation, so you don't have to care about the details of the acceleration. Don't forget the pulley disk.
 
Thanks mfb!
 
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