Auxiliary Field H Problem, Asks for Magnetic Field etc

AI Thread Summary
The discussion revolves around solving a problem related to the auxiliary field H and calculating the free enclosed current. The participant struggles with the textbook's focus on uniformly distributed currents and seeks guidance on determining the free enclosed current. They outline their approach using an Amperian loop and the integral of H, leading to the expression for H in terms of the enclosed current. A key insight shared is that integrating the free current density J over the cross-sectional area will yield the free enclosed current, which can then be used to find the proportionality constant c. This understanding simplifies the problem and allows for further calculations related to the magnetic field.
laz0r
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Homework Statement



attachment.php?attachmentid=57344&stc=1&d=1364790729g.png



Homework Equations



int[H*dl] = I fenc

∇×H = cr^2 [Khat]

∇×H = Jf


The Attempt at a Solution



The textbook I have been assigned (griffiths) only deals with currents that are uniformly distributed and I'm not sure how to go about calculating the free enclosed current for the problem. If I knew how to do that, this problem would be very easy.

Using an amperian loop that extends the radius of the cylinder

∫(closed)H*dl = I fenc

|H|[2*pi*s] = I fenc
H = I fenc / [2*pi*s] [phi hat direction]

Then I would use the cross product ∇×H = Jf in order to calculate Jf, sub in Jf = cr^2 and then solve for c, thus solving part a. I'm just not sure about how to calculate the free enclosed current. if anyone knows the proper formula for this problem I would be grateful to see it.
 

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Hi laz0r. Welcome to PF!

Regarding finding the proportionality constant c: If you integrate Jfree over the cross-sectional area (a<r<b) what should that equal?
 
Ah ok, I understand now. INT[J*dA] = Ifree, then you can use that for your H field later on and find the expression for c immediately by rearranging.
 
laz0r said:
Ah ok, I understand now. INT[J*dA] = Ifree, then you can use that for your H field later on and find the expression for c immediately by rearranging.

You should be able to get c from just ∫J\cdotdA = Io
 
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