Available Energy of Stationary & Moving Particles

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The formula for the available energy of stationary and moving particles incorporates mass, kinetic energy, and the speed of light. The mass of the particle is measured in kilograms when using the metric system, aligning with the definition of a Joule as energy. In CGS units, mass is in grams and speed in centimeters per second, yielding results in Ergs. For imperial units, conversions are necessary for pounds and feet per second to derive energy in BTU or HP. The metric system simplifies calculations, making the conversion factor equal to one.
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In the formula of available energy of a stationary particle and a moving particle:

Ea=(square route of)2MtC^2+(MtC^2)^2+(MkC^2)^2

where:
Mt= mass of stationary particle
Mk= kinetic energy of stationary particle
C= speed of light (299,792,458)

Can someone tell me what the unit of measurement for the mass of the particle.
Thanks
 
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Assuming that C is in m/s and E is in Joules = it would be Kg
 
This may sound like a stupid question, but why?
 
Pretty much from the definition of the Joule

In CGS you would need mass in g, speed in cm/s and you would get an answer in Ergs.
But in imperial units you would need a conversion factor for lbs, ft/s and BTU/HP - it's just that for metric systems the definition of the unit of energy makes the factor =1
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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