Back to Simple Algebra: Solve 76.262 Equation

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To eliminate the denominator of 900 in the equation 76.262 = ((124 + 30b - c)/900) + c, multiplying all terms by 900 is the correct approach. This simplifies the equation effectively without altering the solution. A misunderstanding arose regarding the presence of a denominator of 1000, which was clarified as irrelevant to the solution. The focus remains on maintaining the integrity of the decimal result while solving the equation. Overall, the discussion emphasizes the importance of basic algebraic manipulation to simplify expressions.
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Hello,

Okay, after doing perhaps 1 hour of math a year for 20 years, I realize I forgot a lot!

Can someone please tell what I need to do if I want to get rid of the denominator of 900 in the following expression:

76.262 = ((124 + 30b - c)/900) + c

Please see attachment to see exact equation...

I am trying to find a number I can multiply 124 so that the result can be divided by 900... but I can seem to find it?

Thanks
 

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nevermind ... digging up my old algebra notes, I figured that I can multiply every term by 900...

jeeeezzze,,,
 
The denominators shown in the equation are 1000 and 900. See the "76.262". The common factor is 233253
 
In all due respect, where do you see 1000 as a denominator?
 
To get rid of the 900 we could
simply multiply all terms by 900...no?

(900)76.262 =
((900*124 + 900*30b - 900*c)/900) + 900*c

this works!
thanks
 
simpComp said:
In all due respect, where do you see 1000 as a denominator?

Already explained in my post. It is correct, but unnecessary if you wish to maintain decimalized result.
 
simpComp said:
Hello,

Okay, after doing perhaps 1 hour of math a year for 20 years, I realize I forgot a lot!

Can someone please tell what I need to do if I want to get rid of the denominator of 900 in the following expression:

76.262 = ((124 + 30b - c)/900) + c

Please see attachment to see exact equation...

I am trying to find a number I can multiply 124 so that the result can be divided by 900... but I can seem to find it?

Thanks

Now that I look at the equation again, my picking at the decimal part, ".262" with denominator of 1000 plays no part in the solution. Changing the form would not be useful unless a specific application depended on it.
 
thanks for your help...
it is most appreciated !
 

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