Banked Curves in involving frictions

  • Thread starter Thread starter Addie
  • Start date Start date
  • Tags Tags
    Curves
AI Thread Summary
A car traveling in a circle with a radius of 50 meters and a banking angle of 30 degrees has a coefficient of static friction of 0.3. The maximum velocity for this scenario is calculated to be 22.8 m/s using the equation derived from the forces acting on the car. To find the apparent weight, which is equal to the normal force, one must analyze the vertical forces, but the mass of the car is not needed to compare the apparent weight to the normal weight. The discussion emphasizes deriving results independently for better understanding. Overall, understanding the relationship between forces is crucial for solving these types of physics problems.
Addie
Messages
9
Reaction score
0
Banked Curves involving friction

Problem: A car is traveling in a circle of a radius of 50 meters, on the surface the coefcient of static friction between the car's tires and the road is .3. With a banking angle of 30 degrees.
(I attached a diagram)

So here's what's known:
Radius: R=50 m
Coeffcient of Static Friciton: us=.3
Bank angle theta: T=30 deg

First find: Maximum velocity.
I found this by knowing...
Sum of Fx: m(v^2/r)=NsinT+UsNcosT
Sum of Fy: NcosT-UsNsinT-mg

I find by Equation = Square root of{[rg (sinT+UsCost)]/CosT-(.3 x sinT)}
IT results in Vmax= 22.8 m/s
(here is where I found that equation)

PART 2
Find the apparent weight (hint apparent wieght = Fn)

This the part I'm struggling with.

So i use my Sum of Fx to find N ;
m(v^2/r)=NsinT+UsNcosT=
m(v^2/r)=(mgcosT)sinT+Us(mgcosT)cosT
m(v^2/r)=m[(gcosT)sinT+Us(gcosT)cosT]

then I get nowhere because I divide through by M, and I need to find M or N itself and its practically impossible with just this information...
please help if you can.. any help is apreciated..
 

Attachments

  • physpic.jpg
    physpic.jpg
    11.6 KB · Views: 507
Last edited:
Physics news on Phys.org
Addie said:
First find: Maximum velocity.
I found this by knowing...
Sum of Fx: m(v^2/r)=NsinT+UsNcosT
Sum of Fy: NcosT-UsNsinT-mg
Note that Sum of Fy = 0

I find by Equation = Square root of{[rg (sinT+UsCost)]/CosT-(.3 x sinT)}
IT results in Vmax= 22.8 m/s
(here is where I found that equation)
You really should derive the results for yourself. That's the only way to learn it. (It's easy.)

PART 2
Find the apparent weight (hint apparent wieght = Fn)

This the part I'm struggling with.

You cannot find the apparent weight without knowing the mass of the car. But you can find out how the apparent weight compares to the normal weight (mg). Hint: Use your equation "Sum of Fy = 0" to solve for N.
 
Your right thanks!
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top