- #1
zeromodz
- 246
- 0
If I drop a ball, how far will it fall in 2 seconds?
ΔX = ViT + 1/2AT^2
ΔX = (0)(2) + 1/2(9.8)(2)^2
ΔX = 19.6 m
I tested this, and there is no way an object falls 19.6 m in only 2 seconds. Think about it. Drop something right now and it will only fall like 1 meter in one second. I don't understand. These equations don't fit reality to me. Can someone show me what I am doing wrong?
ΔX = ViT + 1/2AT^2
ΔX = (0)(2) + 1/2(9.8)(2)^2
ΔX = 19.6 m
I tested this, and there is no way an object falls 19.6 m in only 2 seconds. Think about it. Drop something right now and it will only fall like 1 meter in one second. I don't understand. These equations don't fit reality to me. Can someone show me what I am doing wrong?