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TaxiDriver113
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Homework Statement
A 3 kg block is held against a spring (k=580nt/m) at the bottom of a frictionless 25 degree incline. The spring is compressed 0.18m. How far along the incline does the block go when released.
Homework Equations
Usp=1/2kx^2
The Attempt at a Solution
So far the only thing I've been able to do was calculate the velocity which i got to be 1.65m/s if I did it correctly.
Usp= 1/2 * 580 * .18^2
= 9.396
then I did this equation but I didn't know exactly what h was that I was trying to calculate. I think i just ended up calculating how much the spring was compressed and I already knew that.
9.396 + (1/2)(3)(0) = (3)(9.8)(h) + (1/2)(3)(1.654^2)
9.396 = 29.4h + 4.103
h = .18
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