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A 170 g block is launched by compressing a spring of constant k=200N/m a distance of 15 cm. The spring is mounted horizontally, and the surface directly under it is frictionless. But beyond the equilibrium position of the spring end, the surface has coefficient of friction mu = 0.27. This frictional surface extends 85 cm, followed by a frictionless curved rise, as shown in the figure.
After launch, where does the block finally come to rest? Measure from the left end of the frictional zone.
delta,x=(u^2)/2*mu*g
u0=1/2*k*x0^2
I found u0 by using u0=1/2*k*x0^2 to be 2.25 and worked out delta,x to be 4.9967m which has me stumped as to what to do next? any help will be useful thanks
After launch, where does the block finally come to rest? Measure from the left end of the frictional zone.
Homework Equations
delta,x=(u^2)/2*mu*g
u0=1/2*k*x0^2
The Attempt at a Solution
I found u0 by using u0=1/2*k*x0^2 to be 2.25 and worked out delta,x to be 4.9967m which has me stumped as to what to do next? any help will be useful thanks