Blocks on pulley on incline plane

AI Thread Summary
The discussion revolves around calculating the mass M1 in a pulley system with two masses, where M2 is known to be 3.5 kg and accelerates downward at 2.77 m/s². The user has correctly calculated the forces acting on M2 and attempted to apply Newton's second law to find M1, but is confused about the results. They initially calculated M1 to be 3.4 kg but later questioned the accuracy of this result after receiving feedback from an online physics program. The conversation highlights the importance of correctly applying force equations and checking arithmetic, as well as the potential for misunderstanding the normal force in the context of inclined planes. The user seeks clarification on their calculations and the validity of their approach.
Staerke
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Homework Statement



M1 and M2 are two masses connected as shown. The pulley is light (massless) and frictionless.
Find the mass M1, given that M2 (3.5 kg) accelerates downwards at 2.77 m/s2, θ is 25o, and μk is 0.37.

Homework Equations



F = ma
F = mg
Ff = μkN

The Attempt at a Solution



Here's what I've done:
Calculated the force acting on m2 (hanging block)
Fg=3.5*9.81
Fg=34.335
Fma=3.5 * 2.77
Fma=9.695
T=Fg - Fma
T=24.64

Now on to second block
I know these forces are acting on it:
X-direction:
T - Ff - x component of gravity
Y direction
N - y component of gravity

Gravity components:
x = m*g*sin(θ), y = m*g*cos(θ)

I'm only concerned about the forces in the X direction. I know it's accelerating at 2.77 m/s^2

Here's what I put in my calculator
solve(24.64-m*9.81*sin(25)-.37m*9.81*cos(25)=m*2.77,m)
I get 3.4 kg

I have no clue what I'm doing wrong here. This makes sense to me, I really don't understand what I'm missing. Any advice would be greatly appreciated.
The only thing I can think of is if N =/= m*9.81*cos(25) which would throw me off. But I can't figure out why it wouldn't be.
 

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Hi Staerke! :smile:
Staerke said:
Here's what I've done:
Calculated the force acting on m2 (hanging block)
Fg=3.5*9.81
Fg=34.335
Fma=3.5 * 2.77
Fma=9.695
T=Fg - Fma
T=24.64

Here's what I put in my calculator
solve(24.64-m*9.81*sin(25)-.37m*9.81*cos(25)=m*2.77,m)
I get 3.4 kg

I have no clue what I'm doing wrong here. This makes sense to me, I really don't understand what I'm missing. Any advice would be greatly appreciated.

(I haven't checked the arithmetic, but …) the method looks ok to me. :confused:

Why do you think it's wrong?
The only thing I can think of is if N =/= m*9.81*cos(25) which would throw me off. But I can't figure out why it wouldn't be.

If we do F = ma in your y direction, a = 0, so your N = mgcosθ is correct.
 
tiny-tim said:
Hi Staerke! :smile:


(I haven't checked the arithmetic, but …) the method looks ok to me. :confused:

Why do you think it's wrong?


If we do F = ma in your y direction, a = 0, so your N = mgcosθ is correct.

CAPA (the online program my school uses for physics) says it's wrong... Starting to question whether I believe it.
 
Staerke said:
Here's what I put in my calculator
solve(24.64-m*9.81*sin(25)-.37m*9.81*cos(25)=m*2.77,m)
I get 3.4 kg

I've checked the arithmetic now, and i don't get 3.4 :redface:

(I used 3.5(g - 2.77)/{g(sin25° + 0.37cos25°) + 2.77} … is that the same?)

(standard check … you did use ° and not rad?)
 
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