Bus Speed Needed to Coast to Top of 0.88m Hill - Homework Solution

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To determine the speed needed for a bus to coast to the top of a 0.88 m hill, the conservation of energy principle is applied. The equation used is k1 + u1 + Wnc = k2 + u2, which simplifies to 0.5mv^2 = mgy when considering initial kinetic energy and gravitational potential energy at the hill's peak. The mass cancels out, leading to the formula v^2 = gy/0.5. Substituting the values, the required speed is calculated to be approximately 4.15 m/s. This solution effectively demonstrates the application of energy conservation in physics problems.
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Homework Statement


A bus runs out of fuel as it approaches a hill. If the hill is 0.88 m high, how fast must the bus be traveling in order to coast just to the top of the hill?


Homework Equations


?


The Attempt at a Solution


I'm so stuck and it's drving me crazy can someone please give me a hint or something
 
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Use conservation of energy. Does that help?
 
Wouldn't I need to know the mass to use conservation of energy though?
 
nevermind got it
k1+u1+Wnc = k2 + u2
.5mv^2 + 0 + 0 = 0 + mgy
v^2= mgy/.5m
v^2= gy/.5
v= 4.15 m/s
 
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