- #1
marc017
- 7
- 0
My first post let's see if i did this typing right, if not please forgive me...
[tex]\int \frac{(1+ln x)^2}{x}\,dx[/tex]
Trying to attack it by using substitution..
Using...
u = 1 + ln(x) , du = 1/x
[tex]
\begin{align}
\int \frac{(1+ln x)^2}{x}\,dx \\
&= \int (u)^2\,du \\
&= \frac{u^3}{3} + C \\
&= \frac{(1+ln x)^3}{3} + C \\
\end{align}
[/tex]
Where did I go wrong?
Homework Statement
[tex]\int \frac{(1+ln x)^2}{x}\,dx[/tex]
Homework Equations
Trying to attack it by using substitution..
The Attempt at a Solution
Using...
u = 1 + ln(x) , du = 1/x
[tex]
\begin{align}
\int \frac{(1+ln x)^2}{x}\,dx \\
&= \int (u)^2\,du \\
&= \frac{u^3}{3} + C \\
&= \frac{(1+ln x)^3}{3} + C \\
\end{align}
[/tex]
Where did I go wrong?
Last edited: