Calculate DeBroglie Wavelength & Kinetic Energy of Electron

AI Thread Summary
To calculate the DeBroglie wavelength of an electron with energies of 1.0 eV and 100 eV, the formula λ = h/p can be used, where p is the momentum derived from kinetic energy. The user successfully calculated the wavelength for 1.0 eV as 1.23 x 10^-9 m. For 100 eV, the user inquired about multiplying by 1.6 x 10^-19 to find the correct energy value before substituting it back into the equation. There was a clarification needed regarding the expression for momentum, suggesting a potential typo in the user's attempt. The discussion emphasizes the application of the DeBroglie wavelength formula in relation to electron energy levels.
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Homework Statement


What is the DeBroglie wavelength of an electron whose energy is (a) 1.0eV (b) 100eV?
What is the kinetic energy in eV of an electron whose DeBroglie wavelength is that of visible red light at 650nm?


Homework Equations


λ=h/p = h/mv h = Planck's constant mv = particle

The Attempt at a Solution

 
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Well, what have you tried? Where did you get stuck?
 
i used the formula λ=h/(Em)^1/2 and correctly got 1eV to equal 1.23x10^-9.
For 100eV would i just multiply 100 by 1.6x10^-19? then plug it back into the equation?
 
That should work.

Did you really mean to use p=(Em)1/2 or is that a typo -- there is a missing number in the expression?
 
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