- #1
pyroknife
- 613
- 3
I attached the circuit.
I need to find I_1, Voltage drop across R1, voltage drop across R2, and I_2. We're assuming the diode is 'not' ideal.
Vin=5V. R1=R2=1kohm
R3=2kohm
voltage across R2=Vin=5V
I2=5/1kohm=5mA
The real diode drops about 0.7 V. So using voltage divider gives voltage across R1=(R1/(R1+R3))*(5-0.7)=1.43V
Then I1=1.43/1k=1.43mA
Is this the right idea?
I need to find I_1, Voltage drop across R1, voltage drop across R2, and I_2. We're assuming the diode is 'not' ideal.
Vin=5V. R1=R2=1kohm
R3=2kohm
voltage across R2=Vin=5V
I2=5/1kohm=5mA
The real diode drops about 0.7 V. So using voltage divider gives voltage across R1=(R1/(R1+R3))*(5-0.7)=1.43V
Then I1=1.43/1k=1.43mA
Is this the right idea?