Calculate Maximum Water Boiled from 12.0V Car Battery

AI Thread Summary
To calculate the maximum amount of water that can be boiled into steam using a 12.0-V car battery, one must first determine the total energy available from the battery, which is 7.56 x 10^5 C of charge. The energy can be calculated using the formula E = V * Q, where V is the voltage and Q is the charge. Since the water is already at 100 degrees Celsius, the energy from the battery will be used to change the phase of the water from liquid to steam without raising its temperature further. Assuming no heat losses, all energy from the battery is utilized for this phase change. The final calculation will yield the maximum kilograms of water that can be converted to steam.
arod2812
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Homework Statement


A typical 12.0-V car battery can deliver about 7.56 x 105 C of charge before dying. This is not very much. To get a feel for this, calculate the maximum number of kilograms of water (100 degrees C) that could be boiled into steam (100 degrees C) using energy from this battery.


Homework Equations


I am not sure how to solve for kilograms. How do I use what I get from solving equation below to calculate how much water could be boiled into steam??


The Attempt at a Solution


V= EPE/ q0
 
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The water is already at 100C, that means that it is already changing phase. If there is not heat losses then all the energy produced by the battery goes into changing the phase of the water.
 
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