Calculate Power for Lifting 58kg Object 12m in 5.6s | Step-by-Step Formula Guide

[nevag07]

an object of 58kg is lifted 12 meters in 5.6 seconds, calculate the power? I just want to know the formula to use please and thank you

 

[OlderDan]

an object of 58kg is lifted 12 meters in 5.6 seconds, calculate the power? I just want to know the formula to use please and thank you

https://www.physicsforums.com/showthread.php?t=110015

 

[kyle8921]

Power is defined as the rate at which work is done, or the amount of energy transferred per unit time. In this case, the work being done is lifting the object, and the time it takes to lift the object is 5.6 seconds. Therefore, the formula for power is:

Power = Work / Time

To calculate the work, we need to first determine the force needed to lift the object. This can be found using Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a).

So, F = m * a

The object has a mass of 58kg, and it is being lifted vertically, so the acceleration due to gravity (g) can be used as the acceleration in this case. The value of g is approximately 9.8 m/s^2.

Therefore, F = 58kg * 9.8 m/s^2 = 568.4 N

Next, we can calculate the work done by multiplying the force by the distance lifted (12 meters).

Work = Force * Distance = 568.4 N * 12 m = 6820.8 Joules

Now, we can plug these values into the power formula:

Power = Work / Time = 6820.8 J / 5.6 s = 1218.6 Watts

Therefore, the power required to lift a 58kg object 12 meters in 5.6 seconds is approximately 1218.6 Watts.