Calculate the energies of the six lowest states

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To calculate the energies of the six lowest states for a particle in a 2D box with dimensions Lx = L and Ly = ½ L, the relevant energy equation is E = (h²π²(n1² + 0.5n2²)) / (2mL²). There is confusion regarding the derivation and application of this equation, as the user has mistakenly presented two different energy equations. It is essential to understand how to separate the wavefunction and apply the correct boundary conditions for a 2D system. Reviewing the derivation of the energy equation will clarify the setup of the problem. Properly applying these principles will lead to the correct calculation of the energy states.
acusanelli
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Homework Statement



Suppose that a particle of mass m is confined to move in the x-y plane in a 2-dimensional box of length Lx = L and LY = ½ L. Calculate the energies of the six lowest states.


Homework Equations


not sure to set up this problem?


The Attempt at a Solution


the most I can get is
E = (h^2π^2(n1^2+.5n2^2))/ 2mL^2
E = (h^2π^2)/ mL^2
and I don't think this is right
 
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Why do you have two energy equations? You know how to separate the wavefunction and solve for it in 2 dimensions. What can you say about the total energy after you separated the variables?
 
thats because I don't know how to set the problem up, i pulled those equations out of the book and am not sure what I am doing
 
You should read how the first equation you listed was derived. That way you can reproduce it for your problem.
 
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