Calculate the moments Mx, My and the center of mass

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The discussion focuses on finding the equation of a line, specifically g(x), that passes through the point (4, 3). Initially, there is confusion regarding the equation f(x) = x, which is incorrect for this point. The correct slope of the line is determined to be 3/4, leading to the equation y = 3x/4. Participants clarify that the equation must be properly formatted to be valid. The conversation concludes with a sense of understanding and agreement on the correct equation.
huybinhs
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Homework Statement



2010-10-20_2217.png



2. The attempt at a solution

I'm working on #49 ONLY.

I know the top line equation is f(x) = x

but I need to find the g(x), so how can I find with the point is given (4,3). Please help!
 
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huybinhs said:

Homework Statement



2010-10-20_2217.png



2. The attempt at a solution

I'm working on #49 ONLY.

I know the top line equation is f(x) = x
No, it isn't. How could it be, if it goes through (4, 3)?
huybinhs said:
but I need to find the g(x), so how can I find with the point is given (4,3). Please help!
What is g(x) supposed to represent? I am assuming that what you are calling f(x) is the line through (0, 0) and (4, 3).
 
Mark44 said:
No, it isn't. How could it be, if it goes through (4, 3)?
What is g(x) supposed to represent? I am assuming that what you are calling f(x) is the line through (0, 0) and (4, 3).

I got it! It is the slope of the line = 3/4, so the equation line is 3x/4 ;)
 
Technical point: The equation of the line is y = 3x/4. 3x/4 is not an equation (there's no = .)
 
hehe, "what you can't ignore.." http://bayarearoster.com/js/includes/34/b/happy.gif
 
Mark44 said:
Technical point: The equation of the line is y = 3x/4. 3x/4 is not an equation (there's no = .)

Gooooooooooot it ;)
 
Incognition said:
hehe, "what you can't ignore.." http://bayarearoster.com/js/includes/34/b/happy.gif

Agree ;)
 

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