Calculate Velocity of 3.15 kg Ball Released from Compressed 1.96 m Spring

  • Thread starter Thread starter strugglin-physics
  • Start date Start date
AI Thread Summary
The discussion revolves around calculating the velocity of a 3.15 kg ball released from a compressed spring, with the spring's force described by the equation F = 153x + 12.7x^3. After integrating the force over the compression distance, a value of 341 is obtained, which represents the work done on the ball. This work can be equated to the kinetic energy of the ball using the formula W = 1/2 mv^2. The participants clarify that the units of the work done are indeed consistent with energy, confirming that 341 represents the energy transferred to the ball. The final step involves using the work-energy principle to solve for the ball's velocity.
strugglin-physics
Messages
47
Reaction score
0
The force required to compress an imperfect horizontal spring an amount x is given by F = 153x + 12.7x3 , where x is in meters and F in Newtons. If the spring is compressed 1.96 m, what speed will it give to a 3.15 kg ball held against it and then released?

I know that I will need to take the integral from x=0 to x=1.95, which gives me 341. How do I now get the velocity from this? Any suggestions?
 
Physics news on Phys.org
What physical interpretation has "341"?
What are it's units, in particular: can it be seen as some form of energy?
 
I would believe it to be the Force as that is what the function is.
 
strugglin-physics said:
I would believe it to be the Force as that is what the function is.
Force*meter=Force??
Think again..
 
Oh duh that is the Work! So I use W=1/2mv^2!

Thanks for the help!
 
Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
View full post »
Thread 'Correct statement about a reservoir with an outlet pipe'

Thread 'Correct statement about a reservoir with an outlet pipe'

The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
View full post »

Similar threads

Spring Problem Involving Variables and Constants Only
Replies
3
Views
1K
Kinetic Energy & Momentum of a Ball released from Spring
Replies
6
Views
2K
A block of mass m is dropped onto the top of a vertical spring....
Replies
8
Views
5K
What Is the Sled's Speed When Released from a Compressed Spring?
Replies
8
Views
3K
What is the Velocity of a Block Released from a Compressed Spring?
Replies
4
Views
2K
Spring Potential Energy: Horizontal Spring Problem
Replies
6
Views
2K
Elastic potential energy (spring) problem
Replies
3
Views
2K
Spring compression of a bowling ball
Replies
6
Views
4K
Conservation of Energy: Spring PE: Toy gun on spring
Replies
4
Views
2K
Determine expressions for the following in terms of M, X, D, h and g
Replies
30
Views
1K

Hot Threads

Recent Insights

Back
Top