Calculating Acceleration & Force of Strain Thread

AI Thread Summary
To calculate the acceleration and force of the strain thread, it's essential to define the accelerations of each weight relative to the ground and the movable pulley. The discussion highlights the need for clarity in the problem statement and emphasizes that the questioner should demonstrate prior attempts to solve the exercise. The relationship between the accelerations of the movable pulley and the weights is established, noting that they are equal in magnitude but opposite in direction. Newton's second law is suggested as a method to derive the solution. Clear definitions and structured calculations are crucial for resolving the problem effectively.
irrehaare
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J must count acceleration of each weight and the force of strain thread. Here is a picture:
 

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so nobody know the answer or i wrote quastion to complicated ?
 
Well, for one thing your question is not very clear! What are you trying to do?For another, this is the homework forum and you haven't shown that you have tried anything yourself!
 
of cours i tried but it is a exercaise from book and i have an answer at the end. But my solution is incorrect. So i ask here. And i tried to count forces work on thread on my picture.
 
Uhmm, let a0 be the acceleration of the movable pulley with respect to the ground.
Positive direction downward.
Let a1 be the acceleration of the m1 with respect to the ground.
Let a'2 be the acceleration of the m2 with respect to the movable pulley (that's how the m2 moves in the movable pulley's view).
Let a'3 be the acceleration of the m3 with respect to the movable pulley (that's how the m3 moves in the movable pulley's view.).
So the acceleration of m2 with respect to the ground is a2 = a'2 + a0, the acceleration of m3 with respect to the ground is a3 = a'3 + a0.
And you have a0 = -a1 (The acceleration of the movable pulley and the m1 is the same in magnitude but in opposite direction).
Since the mass of the movable pulley is negligible, the resultant force acts on it must be \vec{0}.
You can use Newton's 2nd law to solve this problem.
Viet Dao,
 
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