Calculating Car Speed from Kinetic Energy: A Helpful Guide"

AI Thread Summary
The discussion focuses on calculating the speed of a car from its kinetic energy using the formula KE = 0.5mv². The user initially miscalculated the speed based on an energy value of 479,609.6 joules and a mass of 1165 kg. A correct approach was provided, leading to the conclusion that the speed is approximately 28.69 m/s, or 103.3 km/h. The user expressed gratitude for the guidance and acknowledged the learning experience. The thread concludes with the problem being marked as solved.
Probie
Messages
24
Reaction score
0

Homework Statement



This is not homework, I am too old for school. I am trying to teach myself accident reconstruction. The equation I have for impact utilizes crush points. The crush points reveals an energy of 479609.6 to crush the car, so what I am trying to figure out is the speed of the car in km/h.. Any help with this is appreciated greatly, thank you.

Is it possible to find km/h from K.E

Homework Equations



I know that KE = .5mv²

let's say the mass = 1165 kg and the K.E = 479609.6


The Attempt at a Solution



411.682 = 479609.6 / 1165

20.289 = sqr (479609.6)

10.144 m/s² = 20.289 / 2

36.532 km/h = 10.144 / .2777
 
Last edited:
Physics news on Phys.org
It's better to do the problem with variables, and not substitute values until the end.

start with E = (1/2)mv^2 and solve for v. Then put in the numbers.

I can't really tell what you're calculating here. You never use your first intermediate result, and the end result is wrong.

you need to supply units for the Kinetic Energy. I suppose they are Joules?
 
Close. Notice the way I worked through the information. You gave yourself a bit of extra work by solving each little piece bit by bit. Somewhere you dropped a number.


K= 479,600 joules (additional digits are insignificant here)
m= 1165 kg

K= .5 mv² v=√(2K/m)
v=√(2•479,000 J/1165 kg)= 28.69 m/s = 103.3 km/h
 
Thank you very much Chi Meson, I was not even close, man did I make a mess. I really appreciate you pointing me in the right direction. Now that I see how it is done, I will not forget this lesson. Thanks again ~ Probie
 
This thread can be marked as solved. Thank you very much again Chi Meson. You people are the greatest in the world. Thanks.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top