Calculating Current in a Circuit with R1 = 10 Ohms and R2 = 8 Ohms

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To find the current through R1 in a circuit with R1 at 10 Ohms, R2 at 8 Ohms, a 9A current source, and an 18V voltage source, Kirchhoff's laws are essential. The current entering a junction must equal the current leaving it, which is crucial for accurate calculations. The initial attempt involved shorting the current source, leading to an incorrect current of 2.25A through R1. Instead, the current source should be treated as an open circuit when applying superposition. Understanding these principles is key to solving the circuit correctly.
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Homework Statement


the question is find the current through R1

R1= 10 Ohms R2=8 ohms
current source=9A
E=18V

Homework Equations


The Attempt at a Solution


I have tried removing the current source and i get a short circuit on R1 and hence i obtain a current of 2.25A
 

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What you are looking for are kirschoff's laws:
The current entering any junction is equal to the current leaving. So at the top I1 enters and use that together with the "voltage law" then you get the answer
 
When using superposition on current sources, you should open, instead of shorting, circuit that branch.

That may be where your problem lies.
 
Yes didn't realize that i needed to make the current source open circuit. thanks!
 
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