Calculating final rotational speed from angular velocity

In summary, the conversation discusses the conversion of 1.5 rev/s to rad/s and the relationship between the quantities in the relevant equation. It is determined that the quantities I(final), I(initial), w(final), and w(initial) are related through the conservation of angular momentum. If I(final) is increased by a factor of 3, w(final) is decreased by a factor of 3 to maintain the conservation of angular momentum. The conversation concludes with confirmation of the correct solution.
  • #1
Anmol Dubey
15
1
Homework Statement
An ice skater is spinning with a rotational speed of 1.5 rev/s. When he extends his arms and one leg, his rotational inertia increases by a factor of three. What is his final rotational speed?
Relevant Equations
Angular momentum is conserved
L = Iw
L (final) = L (initial)
I(initial)*w(initial) = I(final)*w(final)
I have no idea how to go about this. Any help would be appreciated thanks :)
Edit: I converted the 1.5 rev/s to rad/s = 9.4 rad/s
 
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  • #2
What do you know about the quantities in your last relevant equation?
 
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  • #3
Orodruin said:
What do you know about the quantities in your last relevant equation?
Like I = mr2?
w = Δθ/Δt
I didn't get what you mean by quantities
 
  • #4
Anmol Dubey said:
Like I = mr2?
w = Δθ/Δt
I didn't get what you mean by quantities
No, what does the problem formulation tell you about these quantities:
I(final)
I(initial)
w(final)
w(initial)
 
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  • #5
Orodruin said:
No, what does the problem formulation tell you about these quantities:
I(final)
I(initial)
w(final)
w(initial)
Since L is conserved
If I(final) is increased by a factor of 3, the w(final) is decreased by a factor of 3 so that L(final) = L(initial)
I(initial)*w(initial) = I(final)*w(final)
x*9.4 rad/s = 3x * w
so w(final) = 9.4 rad/s / 3
= 3.1 rad/s
Is that correct?
 
  • #6
Anmol Dubey said:
Is that correct?
Yes.
 
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  • #7
Orodruin said:
Yes.
Thank you for helping:biggrin:
 
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