Calculating Fluid Velocity in a Constricted Tube

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To calculate the velocity of water in a constricted tube, the flow rate (Q) is given as 10 liters/min, which can be converted to cubic meters per second. Using the equation Q = v1A1 = v2A2, where A is the cross-sectional area, the velocity in the 5 cm radius tube can be determined. The pressure in the larger tube is 1×10^5 Pa, and the density of water is 1000 kg/m3, allowing for further calculations if needed. The discussion emphasizes that the flow rate remains constant throughout the tube despite changes in radius. Understanding these principles is crucial for solving fluid dynamics problems in constricted tubes.
dylee3
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1. A tube of radius 5 cm is connected to tube of radius 1 cm as shown above. Water is forced through the tube at a rate of 10 liters/min. The pressure in the 5 cm tube is 1×105 Pa. The density of water is 1000 kg/m3. Assume that the water is nonviscous and uncompressible.



2. P=F/A, Q=v1A1 = v2A2



3. no idea

(a) What is the velocity of the water in the 5 cm radius tube in m/s?



thanks for anyhelp
 
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Looks like you know the volume per time that pass through that tube. Volume can be thought of as area times length. The dimension of the tube is known.
 
it doesn't tell us the length of the tube, its not a perfect cylinder. it starts off with a 5cm radius tube, and angles into a 1 cm radius tube, back out to a 5cm radius tube.
 
It doesn't matter where you look in the tube, 10 L pass by each min.
 
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