Calculating Force and Motion on an Inclined Plane

In summary, Femme_Physics is asking for the acceleration of an object that is 12 kN weight that is sliding down an inclined plane. Femme_Physics calculates the acceleration of the object to be equal to delta v/L. The force on the object is calculated to be 7 kN. Question B is a statics question about the static and kinematic friction of an object sliding down an inclined plane.
  • #36
As far as I can tell, you have the right answer.

Are you sure all the problem data correct?
Like that you have an initial speed of 6 m/s decreasing to 3 m/s?
 
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  • #37
I will write the full question for reference

http://img846.imageshack.us/img846/6564/samemethod.jpg



An body whose weight is W proceeds upwards on an incluned plane, slanted to the horizontal axis at angle alpha.
The force (F), acting on the body parallel to the inclined plane, remains constant during the entire action. The friction friction coeffecient between the body and surface is μ.

A) Calculate the force (F) acting on the body, if in the motion of the body its velocity decreases from 6 m/s to 3 m/s

B) What is the work done in this segment?
 
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  • #38
ehild said:
There were fewer mistakes in your posts if you typed in the calculations. And they were easier to read.

ehild

I just noticed that post. Well, it's tons more time-consuming to do it via typing. I'll try though to be as clear as I can, and show it typed whenever I can.
 
  • #39
Good morning Fp! :smile:

No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)
 
  • #40
Femme_physics said:
I just noticed that post. Well, it's tons more time-consuming to do it via typing. I'll try though to be as clear as I can, and show it typed whenever I can.

Well, it is very difficult to read your handwriting, but your comfort is the first.

Have you found the missing force? Hint: look at the solution of the previous problem.

ehild
 
  • #41
I like Serena said:
Good morning Fp! :smile:

No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)
Neat :smile: ! So the work done is just

Fk x AB = 1879 x 30 = 56370 [N x m]Yes?
 
  • #42
ehild said:
Well, it is very difficult to read your handwriting, but your comfort is the first.

Have you found the missing force? Hint: look at the solution of the previous problem.

ehild

Well, yes, if I corrected the kN -> N thing it turns out 1420.28 [N]

I figured that was right, that's what I thought ILS was saying

Well, it is very difficult to read your handwriting, but your comfort is the first.

I'll try be clearer then. I normally write it big with a big marker, in this case though I can see why it's difficult. If you'll ask me to redo it typed I will
 
  • #43
I like Serena said:
No mistake. I believe your answer is correct.
(Unless ehild thinks otherwise. :wink:)

I see only the applied force and friction.

ehild
 
  • #44
ehild said:
I see only the applied force and friction.

ehild

You're right, so Fp's answer is wrong after all.
(Good that I made an exception clause! :smile:)
 
  • #46
Good! :smile:
 
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