Calculating H2/Mg Ratio in Magnesium & HCl Lab

AI Thread Summary
To calculate the H2/Mg ratio in the lab experiment, first convert the volume of hydrogen gas produced into moles using the ideal gas equation. Then, determine the mass of hydrogen gas from the number of moles. Finally, divide the mass of hydrogen by the mass of magnesium used to find the average ratio. Providing specific experimental data is essential for accurate calculations. This method will yield the desired H2/Mg ratio for the lab report.
bertha
Messages
2
Reaction score
0

Homework Statement



Calculate the average ratio of grams of hydrogen gas produced per gram of magnesium. This is part of a lab in which I know how many grams of magnesium were used and how many ml of hydrogen gas was produced

Homework Equations



Mg (s) + 2 HCl ---> MgCl2 + H2

The Attempt at a Solution

 
Physics news on Phys.org
Well, you have not posted any experimental data, so the question - as posted - doesn't make much sense.

Convert hydrogen volume to number of moles, number of moles to mass.
 
how do you convert volume to moles
 
Use ideal gas equation.
 
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Thread 'How to find the pH of a galvanic cell (MIT OCW problem set)'
This is the final problem in this problem set from MIT OCW. Here is what I did to try to solve it The table cited in the problem is below We can easily spot the two redox couples that are in the electrochemical cell we are given. The hydrogen-based electrode has standard potential zero, and the silver-based electrode has standard potential 0.22. Thus, the hydrogen electrode, with the lower potential, is the reducing agent (ie, it is where oxidation happens) and is the anode. Electrons...
Back
Top