Calculating Spacetime Interval for Event A

In summary, the spacetime interval from the origin in frame S to event A is 8 lightseconds. In frame S', which is moving at a speed of 0.5c with respect to S, the spacial distance from the origin to A is 6 lightseconds. This means that the event A lies along the x' axis in frame S'.
  • #1
Monster007
26
1

Homework Statement



The spacetime interval between the origin in frame S and an event, A, is found to be r = 8
lightseconds. In frame S' moving in Standard orientation with respect to S at speed v =
0.5c event A is measured at a distance r' = 6 lightseconds from the origin.

(a) What is the time interval between the origin in S' and event A?

(b) Could an event at the origin and event A be causally related? Explain your answer


Homework Equations




The Attempt at a Solution



I am studying for upcoming exam so the solution isn't as important as understanding the question, but as far as i know the spacetime interval is invariant which is throwing me way off here, I'm certain if i can get part a i understand part b but am completely at sea with part a) any help will be greatly appreciated, cheers.
 
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  • #2
Yes, the spacetime interval is invariant. Question (a) asks for the time interval, not spacetime interval.
 
  • #3
Also, in addition to what BruceW mentioned,

I suspect that when the problem statement said,
"...distance r' = 6 lightseconds..."
it's not asking for the spacetime interval to A, but really asking for the x' component of r. In other words, the distance from the origin to the projection of A onto the x' axis.

It probably would have been clearer if the problem statement was worded, "measured at a distance x' = 6 lightseconds."

In other words, the spacetime interval from the origin to A is 8 lightseconds (true whether one is in S or S', since spacetime intervals are invariant). And in S', the spacial distance (not spacetime distance) from the origin to A is 6 lightseconds. Still in other words, this "6 lightseconds" vector lies along the x' axis itself.

That's my guess as to what the problem statement is trying to say.
 

FAQ: Calculating Spacetime Interval for Event A

Q1: What is the formula for calculating spacetime interval for event A?

The formula for calculating spacetime interval for event A is Δs² = c²Δt² - Δx², where Δs is the spacetime interval, c is the speed of light, Δt is the time interval, and Δx is the distance interval.

Q2: How is the spacetime interval related to the concept of spacetime?

The spacetime interval is a fundamental measure of spacetime, which combines the three dimensions of space (length, width, and height) with the dimension of time. It is a way to measure the distance between two events in four-dimensional spacetime.

Q3: What are the units for measuring spacetime interval?

The units for measuring spacetime interval are typically seconds (s) for time interval, meters (m) for distance interval, and meters squared (m²) for spacetime interval.

Q4: How does the value of spacetime interval affect the classification of an event?

The value of spacetime interval determines the classification of an event as either spacelike, timelike, or lightlike. A spacelike interval (Δs² < 0) represents events that are not causally connected, a timelike interval (Δs² > 0) represents events that are causally connected, and a lightlike interval (Δs² = 0) represents the path of a beam of light.

Q5: Can the spacetime interval be negative?

Yes, the spacetime interval can be negative, which indicates a spacelike separation between two events. This means that the two events are not causally connected and can occur at the same time in different locations in space.

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