Calculating the Magnitude of the force

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To calculate the force on an electron moving at 4×10^6 m/s in a 0.3 Tesla magnetic field at an 8-degree angle, the correct formula is F = qvBsin(θ). The charge of the electron (q) is approximately 1.602 x 10^-19 C. The user initially omitted the magnetic field value in their calculations and later received an incorrect answer due to using the wrong charge value and potentially not setting their calculator to degrees mode. After correcting these issues, the expected result should align with the proper application of the formula. Accurate calculations are crucial for obtaining the correct force magnitude in this scenario.
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Homework Statement



Calculate the magnitude of the force on an electron moving at 4×10^6 m/s at an angle of 8 degrees to a magnetic field of 0.3 Tesla. Give your answer in Newtons.

Homework Equations


the equation that i used was f= qvBsin(8)

The Attempt at a Solution


f = 1.602 E-27(4E6)Sin 8
but i keep getting the wrong answer, what am i doing wrong ,. PLease help me. Thanks
 
Last edited:
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It looks like you didn't include B.
 
oh thank you after i include B i still get the wrong answer. i get 2.68E-22
 
I just noticed you're not using the right value for q, and make sure your calculator is in degrees mode.
 
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