Calculating Volume Change of a Partially Inflated Yoga Ball

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To calculate the volume change of a partially inflated yoga ball, the surface area of the ball is initially measured and then found to be 1.5 times larger when fully inflated. The relevant formulas for surface area (S = 4*π*r^2) and volume (V = [4*π*r^3]/3) are established. By setting up the equation S2 = 1.5*S1, the relationship between the radii of the partially inflated and fully inflated balls can be derived. This relationship allows for the calculation of the volume change factor (F = V2/V1). The discussion highlights the need for clarification on the steps to derive the volume change from the surface area increase.
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Homework Statement



Initially, A yoga ball is partially blown up and its surface area measured. Afterwards, it is filled completely and its surface area is found to be 1.50 times as big as it was recorded earlier. By what factor has its volume changed?



Im not sure how to solve for this? can someone explain please


The Attempt at a Solution

 
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First write down any formulas that you think might help,

Surface area of sphere S = 4*∏*r^2

Volume of a sphere V = [4*∏*r^3]/3

Write down what you know, S2 = 1.5*S1 or

4*∏*r2^2 = 1.5*4*∏*r1^2 simplify and use this to find,

what you want to know, F*V1 = V2 or F = V2/V1 = ? Use the above expression for volume to write out and simplify V2/V1.

Does this get you started?
 
No, I don't understand your steps of what to do.
 
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