Calculating Volume of Weather Balloon to Lift 4220kg Package

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To lift a 4220kg package, a weather balloon weighing 507kg must have a specific volume filled with helium at standard temperature and pressure (STP). The buoyant force must equal the combined weight of the balloon, package, and helium. The calculations indicate that a volume of approximately 4260 m^3 is required. The buoyant force is derived from the equation balancing the weights and the volume of helium. Understanding the densities of air and helium is crucial for accurate calculations.
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A 507kg weather balloon is designed to lift a 4220kg package. What volume should the balloon have after being filled with helium at STP in order that the total load can be lifted.

I have no idea how to start this problem...
 
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This is a bouyancy problem. Get to the Archemedes section of your text. Find densities of air and helium.

The bouyant force balances the total weight of the balloon , tha package and the helium gas.

I get a volume of 4260 m^3.
 
Last edited:
All right, so:

W(balloon) + W(package) W(helium) = F(bouyant)
4973.67 + 41398.2 + [0.179 * volume * 9.81](heluim) = F
= 1.29 * volume * 9.81

But what do I put if for volume..??
 
got it thanks
 
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