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It would be definitely algebra.Krylov said:Otherwise, I am afraid that your next question will be: "To which category of mathematics does it belong?"
It would be definitely algebra.Krylov said:Otherwise, I am afraid that your next question will be: "To which category of mathematics does it belong?"
You don't need to assign units to either side of the f(x)= equation, they're dimensionless. But you can rewrite the ##e^x## as ##e^{\lambda x}## where ##\lambda=1m^{-1}##.Stephen Tashi said:Lets try this: Suppose there is a random variable X , measured in meters, that has its density defined on interval ## [0, ln (2) ] ## by ##f(x) = C( 2 - e^{x}) ## where ##C## is the normalizing constant ##int_{ 0}^{ln (2)} {(2 - e^ {x})} dx##.haruspex said:I'm sorry, I am not grasping your point.
A experimenter who measures ##X## in centimeters can convert the above density function to the appropriate density for##X## when ##X## is measured in centimeters. I agree that assigning units to the left and right hand sides of ##f(x) = C( 2 - e^{x})## is a confusing or impossible task. But I don't agree that the ##e^x## in the equation implies that the equation describes a physically impossible situation or that it makes it impossible for a experimenter measuring X in different units to convert the above density to his system of measurement.
haruspex said:You don't need to assign units to either side of the f(x)= equation, they're dimensionless. But you can rewrite the ##e^x## as ##e^{\lambda x}## where ##\lambda=1m^{-1}##.
You are right.Stephen Tashi said:From my point of view the probability density function f(x) is not dimensionless. L
Then let me put it a different way. In the post in which you brought up this issue, λ was the average number of events in a specific, fixed time interval, and the algebraic expression featured eλ. It seems to me that this way of defining λ makes it a pure number, so dimensionless, so no problem. It only becomes a problem if you then say, oh, but clearly it is really a rate, i.e. λ per that interval. But if it is to be thought of as a rate then that is how it should appear in the equation, eλt.Stephen Tashi said:I don't see arguments of the form "You can rewrite ..." as having any bearing on question.
Thanks for the appreciation.anorlunda said:I normally associate dimensions with degrees of freedom, as in 3D space or 4D spacetime.
A point-like particle can be described in 3D space with three coordinates. An asymmetric object needs 3 coordinates, plus 3 angular rotations to describe it's position-orientation. Aren't those rotations on an equal footing with translations as being dimensions?
p.s. I normally eschew semantic discussions, but this one caught my fancy. Nice thought provoking Insights article @haruspex
So, it may be worthwhile exploring this, as you have done in your Insight.haruspex said:The ability to represent angles as a dimension slightly increases the power of DA.
There may be other not-so-slight modifications.This kind of addition can cope with adding items of different dimension. That is, to fit with the ϑ Dimension concept, I could define a complex number as an ordered pair, one of 0 dimension and one of dimension ϑ.
I'm not suggesting any modification to the way we represent or perform complex addition. The consideration of alternative representations was to illustrate that, unlike regular addition, adding a real to an imaginary can cope with their having different dimensions.robphy said:There may be other not-so-slight modifications.
That's a fascinating thread. The comments most relevant to my article concern cycles.robphy said:this abstract discussion might be useful about what may be going on with regard to units (and dimensional analysis) in general:
https://golem.ph.utexas.edu/category/2006/09/dimensional_analysis_and_coord.html
What do you want me to consider about it ?robphy said:Consider http://www.wolframalpha.com/input/?i=series(exp(x/a),x)
##
\exp(\frac{x}{a})=1+\frac{x}{a}+(\frac{x}{a})^2/2+(\frac{x}{a})^3/6+(\frac{x}{a})^4/24+(\frac{x}{a})^5/120+...
##
with ##a## as a dimensionless quantity but ##x## with units of length.
robphy said:What are the units on the right-hand side?
Stephen Tashi said:That depends on the units of the constants 1,2,6,24,120...
For example, the equation ## y = 1 + 5x + 2x^2## can describe a physical situation where ##y## is in units of Newtons, x is in units of meters, 1 is in units of Newtons, 5 is in units of Newtons per meter and 2 is units of Newtons per meter squared.
Can an object have a position given by ## y = e^x## ?
robphy said:In the series expansion for exp(x/a), all of those numbers are pure [dimensionless] numbers... they are part of the definition of exp(z), where z is dimensionless.
I'm not making that assumption.Thus, the only thing that carries units is "x"
No, ## y = e^x## cannot be a position equation...
You could have, say, ##y=Ae^{(-t/\tau)}##, where ##A## has units of length, and ##t## and ##\tau## have units of time.
Stephen Tashi said:If an experimenter fits an equation of the form ## y = e^t ## to his data where ##y## is in meters and ##t## is in seconds, he has described a physical relation unambiguously and a different experimenter who wishes to measure distance in centimeters and time in minutes can figure out how to create an equivalent equation using those units of measurement.
It may be true that it would more convenient for the second experimenter if the first experimenter had written his results in a different form.
In most of my examples there are no complex numbers, yet it adds a dimension. Checking that dimension would sometimes indicate algebraic errors, as with the other dimensions. E.g. I might wish to obtain an expression for the angular momentum of something. If the expression I get has dimension ML2T-1 instead of ML2T-1Θ then I know I have gone wrong.Torbjorn_L said:It looks to be analogous to the use of the mathematical dimension i and so doesn't add to the algorithms for solving physical problems
I've been working on that, and I believe I can make that work now.Torbjorn_L said:It is perhaps best seen in the analysis of the Planck constant, which gives nonsensical results.
As I pointed out, that solves nothing. You could equally make mass dimensionless by thinking of all masses as fractions of some standard mass. You may counter that the standard mass has dimension, so any fraction of it has dimension, but that is different. Saying A is some fraction of B means it is a fraction multiplied by B; it does not mean that A is that fraction as a mere number. Likewise, I would argue that a whole circle has dimension Θ, so any fraction of it has dimension Θ.Torbjorn_L said:Treat angles (phases, ...) as fractions of a circle.
Baluncore said:like how do you represent a fractional dimension such as when you take a square root. Or how do you represent a dimensioned variable that is raised to a non-integer power.
Baluncore said:A measurement without units is meaningless. Consider a measured value, complete with units as an input to a process. The units identify the dimension of the value. Convert that value to SI using known conversion factors. The dimension will not change.
Proceed with the computations while tracking any and all the combinatorial changes of dimensions. Adding or comparing apples and oranges will raise an immediate runtime error.
No, you are saying that.Stephen Tashi said:You are saying that "dimensions" are identified by the SI "units of measure" - i.e. that the "unit of measure" is more fundamental than the concept of "dimension".
I refer to simple numerical addition. In a complex number, the operator i serves to keep two numbers apart and so precludes their immediate numerical addition, even though they have the same fundamental physical dimension. They remain independent members in a set, or a data structure.Stephen Tashi said:Why make the assumption that adding different dimensions is an error
Baluncore said:I refer to simple numerical addition.
Dimensional analysis is used as one check on the integrity of physical equations. It does not however detect all errors.
Baluncore said:I refer to simple numerical addition.
In The Physical Basis of DIMENSIONAL ANALYSIS, on page 10;Stephen Tashi said:So do I. Why is it necessarily an error?
Ain A. Sonin said:A base quantity is defined by specifying two physical operations:
a comparison operation for determining whether two samples A
and B of the property are equal (A=B) or unequal (A≠B), and
an addition operation that defines what is meant by the sum
C=A+B of two samples of the property.
Base quantities with the same comparison and addition operations are of
the same kind (that is, different examples of the same quantity). The
addition operation A+B defines a physical quantity C of the same kind as
the quantities being added. Quantities with different comparison and
addition operations cannot be compared or added; no procedures exist for executing such operations.
OK, but that passage is a statement of assumptions. By the same conventional wisdom (i.e the usual assumptions of dimensional analysis) angles are dimensionless. The Insight under discussion challenges conventional assumptions. So I'm questioning the basis for the conventional assumptions.Baluncore said:In The Physical Basis of DIMENSIONAL ANALYSIS, on page 10;
The term equation implies mathematical equality. Equality of numbers, units and dimension.Stephen Tashi said:The assumption that the left and right hand sides of an equation describing a physical law must have the same dimension is essentially an empirical finding.
You could not publish such a discordant result because it would not survive the dimensional analysis of peer review. The result would undermine the physics we describe with mathematics.Stephen Tashi said:So dimensional analysis can detect an "error" in an equation the sense of detecting that the equation isn't provable from the fundamental laws. But such an "error" doesn't imply that the equation describes an impossible experimental result.
Dimensional analysis is usually referred to physical magnitudes, and following this definition of dimension as a physical magnitude with units and measurable it belong to physics. Then again everything physical is usually analyzed mathematically.Demystifier said:I have a related question for everybody. Does the dimensional analysis belongs to mathematics? Or should it be considered as a part of physics?
Actually meter or second are physical units, and there's a distinction between units like meter and second and there corresponding physical magnitudes like length and time referred to standards that are subject to physical conditions like a platinum bar or an atomic frequency.I think in this thread it is not so clear what the OP refers to as dimension, I think he means a measurable unit that adds more information to physical quantities with angular components when it is not simply treated as dimensionless real number since it seems odd to think that radians or degrees depend on physical conditions like for instance temperature in the length case.Can the notion of dimension (like meter or second) make sense without referring to a physical measurement?
No, but modelling it on 3 vectors, one could make the product of any two of i, j, k like a cross product, so the operator has dimension Θ, but the product of i with i etc. like a dot product.DaTario said:consider the application of these notions to quaternion formalism
Not sure what you mean. It is already the case that the form of many equations would be different if we were to use a complete circle as the unit of angle instead of using radians.DaTario said:it seems that an argument exists saying that we should avoid adding entities of different dimensions for the following reason. If one does so, the matematical shape of the formula would depend on the choice of units.
I believe the form of the equations would be the same, but the π related coefficients would have a different value since angle dimension is then being measured in different units. Is that not why 2π often appears in physics formulas, because of the mathematically convenient radian unit we have chosen to use for the angle dimension.haruspex said:It is already the case that the form of many equations would be different if we were to use a complete circle as the unit of angle instead of using radians.
Yes, I was not sure what DaTario meant by a different "form". From the reference to units, I presumed DaTario would regard the appearance of a factor of 2π as being a different form, but, like you, I would consider that the same in form, just different in detail.Baluncore said:I believe the form of the equations would be the same, but the π related coefficients would have a different value since angle dimension is then being measured in different units. Is that not why 2π often appears in physics formulas, because of the mathematically convenient radian unit we have chosen to use for the angle dimension.