Can Compressed Air Power a Car Efficiently?

In summary: Q). So, Q = 1.2 x 10^9 J. Again, this is an upper estimate and does not take into account any losses or inefficiencies in the engine. (d) It is difficult to determine if this car is practical without more information about the engine and its efficiency. However, based on the calculations above, it does seem feasible for short distances under 45 miles, assuming ideal conditions and no losses. In summary, we investigated the claims of air-car entrepreneurs by using thermodynamics to estimate the energy output and range of an air car with a tank capacity of 300 liters at a pressure of 300 bar. We found that the car could potentially travel up to 10,000
  • #1
dlw902
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Homework Statement



There has been some interest in automobiles that run on compressed air. Let's use thermodyanmics to investigate the claims of air-car entrepreneurs. The air c ar is suppsoed to have a tank with a capacity of 300 liters, at a pressure of 300 bar. While details of teh engine are hard to come by, (likely some type of high efficiency turbine, or perhaps based on hydraulics), let's obtain an upper estimate of the energy output by assumign taht the engine operates by reversible expansion of a monotomic ideal gas. Let's also assume that the initial temperature of the gas is 300K.

(a) How many moles of monatomic, ideal gas are present in the tank?

(b) Assume the gas expands by reversible, adiabatic expansion to a final pressure of 1 bar. What are the fianl volumes and temperature? How much work is perforemd? Assuming an engine power of 1 kilowatt (1000J/s) and a speed of 30 miles per hour, what is the range (how far will the car go on one tank of air)?

(c) A somewhat more optimistic estimate is obtained if we assume that the expanding air can absorb heat from teh surroundings. If we assume this as a reversible, isothermal expansion to a final pressure of 1 bar ( at 300 K) what is the range, also assuming the engine power is 1 kilowatt and a speed of 30 mph.

(d) Of course, we expect the efficiency of an actual air car would be somewaht less than this, and there appears to be a little independent confirmation that such cars would work and be reliable, but based on these numbesr, does this car seem practical for some use such as short communities less than 45 miles?

Homework Equations





The Attempt at a Solution



(a) PV=nRT... n=296(300)/(.08206*300)=3,602 moles

not sure how to do the other three :(
 
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  • #2


(b) To find the final volume, we can use the equation P1V1 = P2V2, where P1 = 300 bar, V1 = 300 L, P2 = 1 bar, and V2 is the final volume. Solving for V2, we get V2 = 90000 L.

To find the final temperature, we can use the equation T1/T2 = (P1/P2)^((γ-1)/γ), where T1 = 300 K, T2 is the final temperature, P1 = 300 bar, P2 = 1 bar, and γ = 5/3 for a monatomic ideal gas. Solving for T2, we get T2 = 13.33 K.

To find the work performed, we can use the equation W = ∫PdV, where P is the pressure and dV is the change in volume. Since the expansion is adiabatic, there is no heat transfer and the work performed is equal to the change in internal energy (ΔU). Using the equation ΔU = (3/2)nRT, we can find the work performed to be 1.2 x 10^9 J.

To find the range, we can use the equation W = Fd, where W is the work performed, F is the force, and d is the distance traveled. Since the engine power is 1 kW, the force can be found by dividing the power by the speed (30 mph = 13.41 m/s). So, F = 1000/13.41 = 74.62 N. Plugging in the values, we get d = 1.6 x 10^7 m or 10,000 miles. However, this is only an upper estimate and does not take into account any losses or inefficiencies in the engine.

(c) For an isothermal expansion, the equation remains the same, except the final temperature (T2) is equal to the initial temperature (T1). So, T2 = T1 = 300 K.

Using the same method as above, we can find the work performed to be 1.2 x 10^9 J.

To find the range, we can use the same equation as above, W = Fd. However, since this is an isothermal expansion, the work performed is equal to
 
  • #3


I cannot provide a direct solution to your homework problem. However, I can provide some guidance on how to approach it.

Firstly, it is important to understand the basic principles of thermodynamics, such as the laws of thermodynamics, the ideal gas law, and the concept of work and heat. Without a solid understanding of these principles, it will be difficult to solve the problem.

Secondly, it is important to carefully read and understand the problem, identifying the given information and what is being asked. In this case, the problem is asking for an estimate of the energy output and range of an air-powered car, based on certain assumptions.

To solve the problem, you will need to use the equations and principles of thermodynamics to calculate the final volume, temperature, and work performed in part (b) and (c). You can then use this information to calculate the range of the car in both scenarios.

In part (d), you will need to use your knowledge of thermodynamics to analyze whether the estimated range of the car is practical for certain uses, such as short commutes.

It is also important to keep in mind that this is just an estimate based on certain assumptions, and the actual efficiency and performance of an air-powered car may vary. Further research and testing would be needed to determine the practicality of such a vehicle.

Overall, to successfully solve this problem, you will need a strong understanding of thermodynamics principles, as well as critical thinking and problem-solving skills. I suggest reviewing your notes, textbook, or seeking additional resources if you are having difficulty with any specific concepts. Good luck!
 

Related to Can Compressed Air Power a Car Efficiently?

1. What is thermodynamics?

Thermodynamics is the branch of science that deals with the study of energy and its transformations, particularly in relation to heat, work, and temperature. It also involves the study of the relationship between these variables and the behavior of matter.

2. What are the laws of thermodynamics?

The laws of thermodynamics are fundamental principles that govern the behavior of energy in a system. These laws state that energy cannot be created or destroyed, only transferred or converted from one form to another, and that the total entropy of a closed system will always increase.

3. How is thermodynamics applied in real life?

Thermodynamics has numerous practical applications in everyday life. For example, it helps in the design and operation of engines, refrigerators, air conditioners, and other heat-based systems. It is also used in the study of chemical reactions, phase changes, and energy production and consumption.

4. What is the difference between heat and temperature in thermodynamics?

Heat is a form of energy that is transferred from a hotter object to a colder one, while temperature is a measure of the average kinetic energy of particles in a substance. In thermodynamics, heat is considered a form of energy, while temperature is a measure of the intensity of heat.

5. How does thermodynamics relate to entropy?

Entropy is a measure of the disorder or randomness of a system. In thermodynamics, it is related to the second law which states that the total entropy of a closed system will always increase. This means that systems tend to move towards a state of higher disorder over time.

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