Can Increasing a Spool's Diameter Boost a Motor's RPM?

AI Thread Summary
Increasing the diameter of the spool attached to the motor's output shaft can effectively boost the motor's RPM by increasing the circumference, allowing more belt movement per revolution. Since the motor is a geared type with high torque, changing the internal gearing is not an option. The user is limited to a 12-volt DC supply, ruling out voltage increases as a solution. The application involves raising a light guillotine-style door, and the current 20 RPM is deemed too slow. Therefore, enlarging the spool diameter is the recommended approach to achieve the desired 30 RPM.
jsmith24
Messages
3
Reaction score
0
Hi all,

I have a small DC motor which turns at 20 rpm. The shaft diameter is 6mm, giving a circumference of 18.85 mm. What I want to do is get an effective rate of 30 rpm. Can I do this by simply attaching a spool or spindle to the motor output shaft with a larger diameter? If so, would it be as simple as increasing the diameter by a factor of 1.5?

Thanks,
Jack
 
Physics news on Phys.org
20 rpm! That was not much. Is a gear built-in the motor? Can you change the gear?

But yes: Increasing the diameter of the pulley, you will speed up the velocity of the belt.

Other possibility: Increase the voltage to the motor.
 
Yes, it's a geared motor, sorry! High torque. I'm limited to 12 volts DC, so that's out. I thought it was as simple as increasing the diameter of the shaft (pulley), which would increase the circumference, thereby moving more belt per revolution, effectively increasing the rpm. Thanks!

Jack
 
jsmith24 said:
Yes, it's a geared motor, sorry! High torque. I'm limited to 12 volts DC, so that's out. I thought it was as simple as increasing the diameter of the shaft (pulley), which would increase the circumference, thereby moving more belt per revolution, effectively increasing the rpm. Thanks!

Jack

By increasing the diameter of the pulley (on the motor axis), you are mechanically gearing up the motor. An alternative is to decrease the diameter of the pulley on the load.
 
There's no pulley on the load. It's a simple guillotine-style door. The motor will have a spindle on it, a cord attached to the spindle which will wind up when the motor is forward energized, which, in turn, raises a flat door in a track. When the motor is reverse energized, the spindle reverses, the cord unwinds, the door descends. The problem is that I find 20 rpm (or rather, the amount of cord travel per revolution) too slow. As this was the only motor I found handy, I'm trying to make do. The motor already has plenty of torque to raise the door (which is rather light), so gearing up a bit shouldn't be an issue.

Oh! I forgot to answer part of your question: No, I don't think I can change the internal gearing of the motor.

Thanks!
 
Well, then just increase the diameter of the spool as you suggested in #1.
 
Thread 'Is 'Velocity of Transport' a Recognized Term in English Mechanics Literature?'
Here are two fragments from Banach's monograph in Mechanics I have never seen the term <<velocity of transport>> in English texts. Actually I have never seen this term being named somehow in English. This term has a name in Russian books. I looked through the original Banach's text in Polish and there is a Polish name for this term. It is a little bit surprising that the Polish name differs from the Russian one and also differs from this English translation. My question is: Is there...
I know that mass does not affect the acceleration in a simple pendulum undergoing SHM, but how does the mass on the spring that makes up the elastic pendulum affect its acceleration? Certainly, there must be a change due to the displacement from equilibrium caused by each differing mass? I am talking about finding the acceleration at a specific time on each trial with different masses and comparing them. How would they compare and why?
Back
Top