- #1
Johnx1
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At a post office, there are three parcels of different masses. The mass of the first parcel is y grams. The mass of the second parcel is 500 grams greater than that of the first parcel. The third parcel is 210 grams lighter than the first parcel.
a) Find the total mass, in grams, of the three parcels in terms of y.
My answer: y + (y + 500) + (y - 210) = 3y + 290b) the total mass of the three parcels is 2kg. find the mass of each parcel in grams.
my answer: 2000 = 3y + 290.
1st = 570
2nd = 1070
3rd = 360
a) Find the total mass, in grams, of the three parcels in terms of y.
My answer: y + (y + 500) + (y - 210) = 3y + 290b) the total mass of the three parcels is 2kg. find the mass of each parcel in grams.
my answer: 2000 = 3y + 290.
1st = 570
2nd = 1070
3rd = 360