MHB Can you help me solve (3-2/3)(1-5/7)?

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To solve the expression (3-2/3)(1-5/7), first simplify each term: 3-2/3 equals 7/3 and 1-5/7 equals 2/7. Then, multiply the simplified fractions: (7/3)(2/7) equals 14/21. This fraction can be further simplified to 2/3. Understanding these steps is crucial for mastering similar problems.
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Desperate help is needed; can someone help me calculate (3-2/3)(1-5/7)?
I've been trying and I can't make any sense of it.
I have an exam tomorrow and I'm panicking.
Help?
 
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Hi Ari and welcome to MHB! :D

I've retitled your thread to give a brief description of the problem.

$$\left(3-\frac23\right)\left(1-\frac57\right)=\left(\frac93-\frac23\right)\left(\frac77-\frac57\right)$$

Do you understand the above? If so, can you continue?
 

Thread 'Trigonometry problem of interest'

Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
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